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30z^2+7z-2=0
a = 30; b = 7; c = -2;
Δ = b2-4ac
Δ = 72-4·30·(-2)
Δ = 289
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$z_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$z_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{289}=17$$z_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-17}{2*30}=\frac{-24}{60} =-2/5 $$z_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+17}{2*30}=\frac{10}{60} =1/6 $
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